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Q: How do you factor the expression 20xy?

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2 * 2 * 5 * x * y

It is an algebraic expression

2,5,10,x

2*2*5*x*y

The expression has no rational factors.

4xy

2 * 2 * 5 * x * y

35

(2x - 3y)(2x - 7y)

5xy (2x - 3y + 4 )

If you're looking to factor this expression, then you need to find two values that add up -20, and which multiply to make 4. Unfortunately, no such terms exist, so this expression can not be factored.

5(x^2 - 4xy + 2y^2)

0.4444

I need to; factor each expression 10x + 40 = ?

Nothing is a factor BY ITSELF; you can say that one expression is a factor OF ANOTHER EXPRESSION. IF you don't specify the other expression, the question is meaningless.

This is technically a partial derivative, represented as ∂(20xy)/∂x. The way to calculate this is simple, treat y as a constant, like 20 is in this case. Therefore, the expression is simplified to 20*y*d(x)/dx. d(x)/dx is just 1, so the answer is 20y.

a common factor

There is no factor of the expression in the question.

It is a quadratic expression in x and y. Since it is not an equation it cannot be solved or represent any shape in the 2-dimensional plane.

5x2 - 20xy + 10y2 = 5(x2 - 4xy + 2y2) which cannot be simplified into rational factors.

2 times 2 times 5 times x times y = 20xy

9

the common factor is 1.

64

It is 5*f where f is an expression.

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